Calculating Final NaCl Concentration After Dilution

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SUMMARY

The final NaCl concentration after adding 2uL of 50mM NaCl to a 30uL reaction is calculated to be 3.125mM, which is equivalent to 3.125 x 10^-3M. The dilution factor is determined by the ratio of the added volume to the total volume, calculated as (2 / (2 + 30)) = 1/16. This dilution factor is then multiplied by the original concentration to find the new concentration. The conversion from millimolar to molar is accurately performed by dividing by 1000.

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neoking77
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Hello all, I just want to confirm that I am on the right track for a certain question regarding dilution and concentration

Q: Addition of 2uL of 50mM NaCl to a 30 uL reaction gives a final NaCl concentration of ______ M.

Attempt:
so because you add 2uL to 30uL, the dilution is (2 / 2+30) = 1/16
Then I multiplied the dilution with the concentration for the new concentration
1/16 x 50mM = 3.125 mM

Finally, I converted the mM back to M
3.125 mM (1mol / 1000mmol)
answer = 3.125 x 10^-3M

does this look ok?

thank you in advance
 
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Looks correct to me.
 

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