- #1

mathmari

Gold Member

MHB

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The functions \begin{equation*}f(x)=\frac{1}{3}(x-2)^2e^{x/3} \ \text{ and } \ p(x)=-\frac{2}{3}x+\frac{4}{3}\end{equation*} have exactly two real intersection points at the region $x\geq 0$.

Calculate numerically the area that is between the graphs of these two functions, with accuracy of two decimal digits. For that do we have to claulate numerically the intersections points, using for example Newton's methos? (Wondering)