Calculate the buoyant force on a solid object made of copper

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To calculate the buoyant force on a solid copper object with a volume of 0.2 m^3 submerged in water, the formula B = pVg is used. The initial calculation incorrectly applied the density of copper (8.92 x 10^3 kg/m^3) instead of the density of water. The correct buoyant force should be calculated using the density of water, leading to a final answer of 1.96 x 10^3 N. The discussion highlights the importance of using the appropriate density in buoyancy calculations. The user successfully resolved the confusion regarding the use of copper's density.
BrainMan
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Homework Statement


Calculate the buoyant force on a solid object made of copper and having a volume of 0.2 m^3 if it is submerged in water.

Homework Equations


B = pVg

The Attempt at a Solution


I followed the above equation and did
B = (8.92 x 10^3 kg/m^3)(0.2 m^3)(9.8 m/s^2)
B = 1.74 x 10^4
The correct answer is 1.96 x 10^3
 
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Why do you use the density of copper?
 
mfb said:
Why do you use the density of copper?
I'm not sure it's just part of the formula. p = density
 
A density, sure, but not the one of copper.
 
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mfb said:
A density, sure, but not the one of copper.
Ok thanks! I figured it out.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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