Calculate the Capacitance given the Charge and Potential Difference

Click For Summary
To calculate capacitance, divide the charge in coulombs by the potential difference in volts. The formula for capacitance is C = Q/V, where C is capacitance, Q is charge, and V is voltage. For conversion to picofarads, multiply the result by 10^-12. This method is correct for determining capacitance based on the given charge and potential difference. Proper application of this formula will yield accurate capacitance values.
member 757689
Homework Statement
Find capacitance between two objects; one with charge +30 nC the other with charge -30 nC. Potential difference is 500 V.
Relevant Equations
C = Q/V
Hello, I would like some help on a homework problem. I would think that capacitance would simply be the positive charge's value in C divided by the deltaV value then multiplied by 10^-12 for pF conversion. Does this look like the right approach?
 
Last edited by a moderator:
Physics news on Phys.org
boostlover123 said:
Hello, I would like some help on a homework problem. I would think that capacitance would simply be the positive charge's value in C divided by the deltaV value then multiplied by 10^-12 for pF conversion. Does this look like the right approach?
Yes, it does.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
9
Views
356
Replies
4
Views
2K
Replies
21
Views
2K
Replies
3
Views
3K
Replies
10
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K