Calculate the Capacitance given the Charge and Potential Difference

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SUMMARY

The discussion centers on calculating capacitance using the formula C = Q / ΔV, where C is capacitance in farads, Q is charge in coulombs, and ΔV is the potential difference in volts. The participant correctly identifies that to convert capacitance from farads to picofarads (pF), one must multiply by 10^-12. This approach is confirmed as accurate by another participant, establishing a clear method for solving capacitance problems in physics.

PREREQUISITES
  • Understanding of basic electrical concepts, including charge and potential difference.
  • Familiarity with the formula for capacitance: C = Q / ΔV.
  • Knowledge of unit conversions, specifically from farads to picofarads.
  • Basic algebra skills for manipulating equations.
NEXT STEPS
  • Study the relationship between capacitance, charge, and voltage in different capacitor types.
  • Learn about the effects of dielectric materials on capacitance.
  • Explore practical applications of capacitance in electronic circuits.
  • Investigate advanced capacitance calculations involving series and parallel configurations.
USEFUL FOR

Students studying physics, electrical engineers, and anyone interested in understanding the principles of capacitance and its applications in electronics.

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Homework Statement
Find capacitance between two objects; one with charge +30 nC the other with charge -30 nC. Potential difference is 500 V.
Relevant Equations
C = Q/V
Hello, I would like some help on a homework problem. I would think that capacitance would simply be the positive charge's value in C divided by the deltaV value then multiplied by 10^-12 for pF conversion. Does this look like the right approach?
 
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boostlover123 said:
Hello, I would like some help on a homework problem. I would think that capacitance would simply be the positive charge's value in C divided by the deltaV value then multiplied by 10^-12 for pF conversion. Does this look like the right approach?
Yes, it does.
 

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