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- Homework Statement
- A tiny negatively charged oil drop is held stationary in the electric field between two horizontal parallel plates, as shown below (please see attachment). Its mass is 4.0x10^-15kg.

Question 15,b) Use the fact that the 2 forces balance to calculate the charge on the oil drop. (g = 10 N Kg^-1).

- Relevant Equations
- 1. F - Ma

2. E = F/Q or E = V/D (Electric field strength)

The book gives an answer of Q = 3.2 x 10^-19C

I get an answer of 6.67 x 10^-19C. Workings below:

I get an answer of 6.67 x 10^-19C. Workings below: