Calculate the distance the sled travels

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SUMMARY

The discussion focuses on calculating the distance a sled travels after launching from a ski jump with specific parameters. The sled has an initial speed of 5.0 m/s, a jump height of 16 meters, and a friction coefficient of 0.5. The angle of the ski jump is 53 degrees, and the sled lands 21.6 meters above the ground. Key equations involved include F=ma, Range=Vox(T total), and Y=Voy t + 1/2gt², which are essential for determining the sled's speed at the end of the ramp and the subsequent distance traveled.

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Homework Statement


A sled starts with an initial speed of 5.0 m/2 at the top of a 16 meter high ski jump. The ski jump makes an angle of 53 degrees relative to the horizontal. There is a coefficient of kinetic friction of 0.5 between the sled and the ski jump. Calculate the distance from the sled lands from the base of the jump to the bottom edge of the slope 21.6 meters above the ground.

Homework Equations


F=ma
Range=Vox(T total)
Y=Voy t +1/2g t^2

The Attempt at a Solution


I have no idea where to begin. I know I need to find the speed at the end of the ramp to find the distance the sled lands but am not sure how to find that.
 
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ahardm1 said:
A sled starts with an initial speed of 5.0 m/2 at the top of a 16 meter high ski jump. The ski jump makes an angle of 53 degrees relative to the horizontal. There is a coefficient of kinetic friction of 0.5 between the sled and the ski jump. Calculate the distance from the sled lands from the base of the jump to the bottom edge of the slope 21.6 meters above the ground.
I cannot make sense of that description. Is there a diagram? Have you quoted the text word for word?
 
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