The discussion revolves around calculating the average friction force acting on a sled sliding down a slope. The sled has a mass of 60 kg, descends a 500-meter slope from a height of 10 meters, and reaches a final speed of 8 m/s. Participants are examining the calculations related to forces involved in this scenario.
The discussion is ongoing, with participants raising questions about the correctness of the calculations and the assumptions made regarding the forces acting on the sled. Some guidance has been offered regarding the interpretation of the forces involved, but no consensus has been reached.
Participants have noted that the height of the slope has not been utilized in the calculations, which may be relevant to understanding the overall dynamics of the sled's motion.
You have calculated a propulsive force (F), right?AlexPilk said:F=480/125=3.84 N
Weight=mg=600
600-friction=3.84
1.I think so, it's the force that accelerates the sledharuspex said:You have calculated a propulsive force (F), right?
What direction does that act in?
What direction does mg act in?
(You might have noticed that you have not used the 10m height.)
As in vertically down? You obtained it by dividing momentum by time. What direction was the momentum in?AlexPilk said:2.Downwards