Calculate the frequency, in hertz (level n = 10 to level n = 5)

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SUMMARY

The discussion focuses on calculating the frequency of a photon emitted when an electron transitions from energy level n = 10 to n = 5 in a hydrogen atom. The Rydberg formula, 1/λ = RH ∙ (1/n₁² - 1/n₂²), is applied to derive the wavelength (λ) as 3.0392×10⁻⁶ m. The calculated frequency in hertz is 9.89e14 Hz. However, the user expresses uncertainty about the correctness of their wavelength conversion, indicating a need for clarification on the calculation process.

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Calculate the frequency, in hertz, of the photon that is emitted when a electron falls from level n = 10 to level n = 5 in the H atom.

Enter a numeric answer only, no units.


I tried asking in other places but ppl are so ambiguous about it.
:( please help me.

I used rydberg formula:
1/λ = RH ∙ (1/n₁² - 1/n₂²)
(RH rydberg constant for hydrogen, n₁ lower level, n₂ higher level)

Hence:
λ = 1/ [ 1.09678×10⁷m⁻¹ ∙ (1/5² - 1/10²) ] = 3.0392×10⁻⁶m

and then I converted to Hz = 9.89e14 but i still GOT IT wrong :( Please help me someone!
 
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Check your math, 10-6m doesn't look correct.

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