- #1

dainceptionman_02

- 18

- 4

- Homework Statement
- A rectangular loop (area = 0.15m^2) turns in a uniform magnetic field, B=0.20T. When the angle between the field and the normal to the plane of the loop is π/2 rad and increasing at 0.60rad/s, what emf is induced in the loop?

- Relevant Equations
- ξ=-N(dΦ/dt), Φ=BAcosθ

there are a bunch of problems in this section that ask similar questions, but they ask the amplitude and this doesn't. this is an even problem so i do not have the answer, but my hunch is that it is not an amplitude question. i solved for the amplitude so i am guessing i got this one wrong.

ξ=-N(dΦ/dt) = -NBA(d/dt)(cosθ) = -NBA(-sinθ)dθ/dt, where dθ/dt=ω, which is 0.60rad/s.

the problem states that initially the angle between the field and the normal to the plane is π/2 rad and increasing at 0.60rad/s, which should mean that initially the flux is zero, because Φ=BAcosθ=BAcos(π/2)=0

now, the amplitude, or the maximum emf induced in the loop is ωNBA = (0.60rad/s)(1)(0.20T)(0.15m^2) = 0.018V, but like i said, i think they are asking something else, but i don't know what?

ξ=-N(dΦ/dt) = -NBA(d/dt)(cosθ) = -NBA(-sinθ)dθ/dt, where dθ/dt=ω, which is 0.60rad/s.

the problem states that initially the angle between the field and the normal to the plane is π/2 rad and increasing at 0.60rad/s, which should mean that initially the flux is zero, because Φ=BAcosθ=BAcos(π/2)=0

now, the amplitude, or the maximum emf induced in the loop is ωNBA = (0.60rad/s)(1)(0.20T)(0.15m^2) = 0.018V, but like i said, i think they are asking something else, but i don't know what?