Calculate the mass of CO2 produced from the complete combustion

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SUMMARY

The discussion focuses on calculating the mass of CO2 produced from the complete combustion of 3.79 L of gasoline, specifically octane (C8H18). The balanced chemical equation is 2C8H18 + 25O2 → 16CO2 + 18H2O. The calculation provided yields 8835.8957 g of CO2, which should be reported as 8840 g to reflect three significant figures, consistent with the input data.

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  • Understanding of stoichiometry in chemical reactions
  • Familiarity with the concept of significant figures
  • Knowledge of the density of liquids, specifically octane
  • Basic grasp of chemical equations and molar conversions
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Zhalfirin88
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Homework Statement


Gasoline consists primarily of octane, C8H18

Calculate the mass of CO2 produced from the complete combustion of 3.79 L (1.00 gallon) of gasoline (assume octane, density = 0.756 g/mL) with excess O2

The Attempt at a Solution


The balanced chemical formula would be:

2C8H18 + 25O2 \rightarrow 16CO2 + 18H2O

For my work:

3790mL (octane)* \frac{0.756g(octane))}{mL} * \frac{1 mol (octane)}{114.144g (octane)} * \frac{8 mol (CO_2)}{1 mol (octane)} * \frac {44.00g CO_2}{1 mol CO_2}

= 8835.8957g CO_2

Is it correct? What about significant figures?
 
Last edited:
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Looks correct. Since you start with a number with 3 significant figures and use a conversion factor with 3 sig figs, use three in your answer.
 

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