Calculate the molarity, M, of the NaOH

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The discussion centers on calculating the molarity of sodium hydroxide (NaOH) used in a titration with potassium acid phthalate (KHP). The correct molecular weight of KHP is established as 204.22 g/mol, which is crucial for accurate calculations. The initial calculation of molarity was incorrect due to using an erroneous molecular weight of 71.08 g/mol. The final molarity of NaOH is determined using the formula M = (mass of KHP / molar mass of KHP) / volume of NaOH in liters.

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An amount of potassium acid phthalate (KHP) weighs 0.426 g. The KHP is dissolved in a small amount of water and titrated with 16.98 mL of NaOH. Calculate the molarity, M, of the NaOH.

The following is my answer, but it was wrong. Can anyone help? Thanks

Molecular weight of KHP = 71.08
0.426/71.08/0.01698 = 0.353
 
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The molecular weight of KHP is 204.22 g/mol. Assuming 16.98 mL was the amount needed to reach the end point your calculation is correct except for the molar mass of KHP.
 
Thanks a lot

:smile: :smile: :smile:
 
no problem
 

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