Calculate the pressure experienced by the sensor ?

  • Thread starter Thread starter Colin19
  • Start date Start date
  • Tags Tags
    Pressure Sensor
Click For Summary

Homework Help Overview

The discussion revolves around calculating the pressure experienced by a sensor located at a depth of 0.34 meters in a fuel tank, where the fuel has a specific gravity of 0.7. The problem involves concepts related to fluid mechanics and pressure calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various interpretations of the pressure calculation, with one suggesting the use of a basic pressure formula involving force and area, while another proposes a direct multiplication of depth, specific gravity, and gravitational acceleration. There is also mention of confusion regarding the correct method to apply.

Discussion Status

The discussion includes attempts to clarify the method for calculating pressure, with some participants expressing uncertainty about the logic behind the calculations. While one participant claims to have found the answer, there is no explicit consensus on the correct approach, and some participants question the relevance of the thread.

Contextual Notes

Participants reference the use of specific gravity and the relationship between depth and pressure, indicating a need for clarity on these concepts. There is also mention of external resources and discussions with peers that influence their understanding.

Colin19
Messages
31
Reaction score
0

Homework Statement


A sensor is at rest in a fuel tank , it is at a depth of 0.34m
and the fuel has a specific gravity of 0.7 .
Calculate the pressure experienced by the sensor ?


Homework Equations


I guess Pressure = force/area


The Attempt at a Solution


I considered gravity as the force
And depth as the area
to apply it on the stated equation
Using some site calculator
Result was = 2.0588235294118 Newton/meter^2
 
Physics news on Phys.org
After some revision , I think it's 0.34x0.7x9.81 = p ?
 
Actually it's after asking a friend
 
I'm totally clueless what is the logic behind this and what is the correct method to solve
 
Ok , Thanks I found the answer
Equation :
Used with liquid columns of constant density or at a depth within a substance (example: pressure at 20 km depth in the Earth).
p = Height x density x gravity
where:
P is Pressure
g is gravity at the surface of overlaying material
ρ is density of liquid or overlaying material
h is height of liquid or depth within a substance
...
Got it
 
I feel that this thread is pointless is it possible to delete it . \ :
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
6K
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
7
Views
3K