1. The problem statement, all variables and given/known data Compute for the value of pressure beneath the foot of a person after stomping. The person has a weight of 50kgs, supposed that there is a sensor beneath the foot of the person and after stomping the foot it records a 51.5 kg of weight. The area of the sensor is 2.5 square inch. Stationary weight = 50 kgs measured weight after stomping = 51.5 kg Area of the pressure where change of weight is detected = 2. 5 square inch 2. Relevant equations Pressure = Force / Area Force = mass x acceleration 3. The attempt at a solution Computing for the pressure upon stomping on the sensor is equivalent for Pressure = Force / Area. I have an Area which is 2.5 square inch now,the problem is what is the applied force. Since I have a change of rate of the weight which 51.5 kgs from 50kgs. Can I consider this as the Force as 51.5kg/s/s. Or Force equal to mass x acceleration. The mass would be the default weight that is 50kgs. Then the force is computed as (measured weight - actual weight) / actual weight. Leaving the acceleration as the unknown variable. If I proceed on this method... it would be acceleration = force / mass a = (51.5kg/s/s - 50 kg/s/s )/ 50kg a =.03 s/s. Then going back to the pressure formula P = F / A, P = (mass x acceleration) / area. P = (51.5 kg /s/s x .03 s/s) / 2.5 square inch. Pressure is .618 Kg/ square inch. Please help anyone.