Calculate the quasi-Fermi level of holes and electrons?

  • Thread starter Thread starter yeyintkoko
  • Start date Start date
  • Tags Tags
    Electrons Holes
Click For Summary
SUMMARY

The discussion focuses on calculating the quasi-Fermi levels for holes and electrons in Gallium Arsenide (GaAs) under steady-state conditions. Given the effective density of states of 4 × 1017 cm−3 for the conduction band and 8 × 1018 cm−3 for the valence band, along with a band gap of 1.42 eV, the relevant equations for determining the quasi-Fermi levels are provided. The equations include the intrinsic carrier concentration (ni) and the relationships between the Fermi levels and carrier densities. The user expresses uncertainty about the correctness of the equations presented.

PREREQUISITES
  • Understanding of semiconductor physics, specifically GaAs properties
  • Familiarity with effective density of states (DOS) in conduction and valence bands
  • Knowledge of Fermi level concepts and calculations
  • Proficiency in using thermal energy equations in semiconductor contexts
NEXT STEPS
  • Study the derivation of the intrinsic carrier concentration (ni) in semiconductors
  • Learn about the impact of temperature on Fermi levels in semiconductors
  • Explore the application of the Boltzmann approximation in semiconductor physics
  • Investigate the effects of illumination on carrier densities in semiconductor materials
USEFUL FOR

Students and professionals in semiconductor physics, electrical engineering, and materials science who are involved in the analysis and application of quasi-Fermi levels in semiconductor devices.

yeyintkoko
Messages
14
Reaction score
0

Homework Statement


GaAs has an effective density of states (DOS) = 4 × 1017 cm−3 for the conduction band, = 8 × 1018 cm−3 for the valence band and a band gap of = 1.42 eV.
a) A thin slice of GaAs is illuminated by a cw light source, creating a steady state
density of 1017 cm−3 of electrons and holes. Calculate the quasi-Fermi level of
holes and electrons for the system.

Homework Equations


ni = (NCNV)1/2 (-EG/2kT);
Ei = EG/2 + kT/2 * ln(NV/NC);

Efc-Ei = kTln(n/ni);
Efv-Ei = -kTln(p/ni);

Efc-Ei = kTln(1017/ni);
Efv-Ei = -kTln(1017/ni);

The Attempt at a Solution


My problem is that this equations is right?
 
Last edited:
IMO this belongs in the advanced physics forum.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K