Calculate the rate of energy output of the sun, taking the sun as a blackbody

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The discussion focuses on calculating the rate of energy output of the sun, modeled as a blackbody. The surface temperature of the sun is established at approximately 5800K, and its radius is 6.96x108 m. The formula used is H = εσAT4, where ε is the emissivity (1 for a blackbody), σ is Stefan's constant, and A is the surface area of the sun. The correct calculation yields a power output of approximately 7.87x1023 W/m2, but the discussion highlights a misunderstanding between calculating energy output and the use of radius versus Stefan's constant.

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ninaw21
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1. The surface temperature of the sun is approximately 5800K. Given that the radius of the sun is 6.96x108m calculate the rate of energy output of the sun, taking the sun as a blackbody.

2. H = εσAT4



3. Surface temp = 5800K, Radius of the sun = 6.96x108, Emissivity of a blackbody = 1
H = εσAT4
H/A = (1)(6.96x108)(5800)4
= 7.87x1023W/M2

Am I right??
 
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No. Question is asking for "the rate of energy output" which is power (watts). You also seem to be confusing radius with σ, Stephan's constant.
 

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