1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculate the required current flow in the suspended wire

  1. Feb 17, 2016 #1
    1. The problem statement, all variables and given/known data

    GIANCOLI.ch20.p4546and74.jpg
    In the figure, the top wire is 1.5 mm diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 70 A in each.

    Calculate the required current flow in the suspended wire.

    2. Relevant equations
    F=(I1I2μo*length)/2πr
    F=(r2πρ)/length

    3. The attempt at a solution
    I cancelled length and now have combined:

    (r2πρ)=(I1I2μo)/2πr

    I1 = 70A
    ρ (density of copper) = 8.92g/cm2
    μo = 4π*10-3
    r (on the left side) = .15cm/2
    r (on the right side) = 3.8cm

    I just plug these in and find I2....?
    I have tried to, but I keep getting the wrong answer.. maybe my r's are mixed up? I tried switching them, but still wrong.. I think I am missing something, maybe my wrote down the equations incorrectly.. please help! I don't need the final answer, I'm more interested in learning how to do this type of problem.

    Thank you in advance!
     
  2. jcsd
  3. Feb 17, 2016 #2

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Welcome to PF!
    Did you mean for the length in the second equation to be in the numerator? Does the acceleration due to gravity play any role here?

    Think about the direction of the magnetic force on the the top wire due to each of the bottom wires.

    Since you didn't show your calculation, we can't tell if you did the unit conversions correctly. (Your units for the density of copper are incorrect.)

    What units are you using for expressing μo?
     
  4. Feb 17, 2016 #3
    Oh, yes! The length on the left side is supposed to be in the numerator to cancel. That is my mistake!

    I thought that I could calculate mg (in the equation F=mg) by using r2πρ*length, but I really am not sure that this is correct..
    Would the direction be downward?

    μ0's units are Wb/m2.

    And again, my mistake, the density of copper's units are in kg/m3 not g/cm2.

    I really appreciate your help!
     
  5. Feb 17, 2016 #4
    Here's what I have after I converted everything to meters:

    (0.0015m/2)2*π*(8.92kg/m3) = [(70A) * I2 * (4π*10-3 Wb/m2)]/(2π*0.038m)
    and I found I2 to be 4.27*10-6, so I am doing something very wrong...
     
  6. Feb 17, 2016 #5

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Your value for the density in kg/m3 is incorrect. Be careful with converting cm3 to m3. Also, your value for μo in the SI system of units is incorrect. Check your textbook or notes.

    There are two magnetic forces on the upper wire; one force from each of the lower wires. These forces are vector quantities and so you need to consider the directions of these forces.
     
  7. Feb 17, 2016 #6

    TSny

    User Avatar
    Homework Helper
    Gold Member

    What happened to the "g"? Yes, the direction is downward.

    These are not correct units for μ0.
     
  8. Feb 17, 2016 #7
    OHH! Okay okay! I think I get it!
    Sorry for the many mistakes in values and units, I looked back in the textbook and corrected everything.
    μo = 4π*10-7 Tm/A
    density value is 8960 kg/m3

    And then with 2*Fcos(30) = ρπr2*length*g, I can cancel lengths, the "2", and put it back into the other equation to get:

    ρπr2g = [I1I2μocos(30)]/(πr)

    I got my correct answer with this, thank you so very much for your help! c: I really appreciate it!
     
  9. Feb 17, 2016 #8

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Great. Good work!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Calculate the required current flow in the suspended wire
Loading...