Calculate the resolution in linear travel of the tape

Click For Summary
SUMMARY

The discussion focuses on calculating the resolution in linear travel of a tape driven by a 24V DC motor with an optical encoder featuring 500 divisions. The resolution is determined to be 0.2mm per pulse, derived from the motor's pulley circumference of 100mm divided by the number of pulses. The tape velocity is calculated at 2.8009 m/s based on a motor speed of 28.009 rev/s. The accuracy of the velocity measurement remains unclear, particularly regarding the smallest deviation the encoder can detect.

PREREQUISITES
  • Understanding of optical encoders and their pulse output
  • Knowledge of basic motor speed vs. voltage relationships
  • Familiarity with circumference calculations and linear travel
  • Basic concepts of measurement accuracy and tolerance bands
NEXT STEPS
  • Research the specifications and limitations of optical encoders
  • Learn about motor speed vs. voltage graphs and their applications
  • Explore methods for calculating measurement accuracy and tolerance bands
  • Investigate the impact of pulse frequency on velocity measurement
USEFUL FOR

Engineers, robotics enthusiasts, and anyone involved in motion control systems who require precise measurements of linear travel and velocity in motor-driven applications.

polyperson
Messages
38
Reaction score
0
Nobody replying, so I’ve reframed the question

A 24V DC motor has an optical encoder with 500 divisions which outputs the pulse frequency to an electronic counter/timer. The motor has a flat pulley of 31.827mm diameter used as a tape drive.

(a) Calculate the resolution in linear travel of the tape

(b) Determine the velocity of the tape if the motor is supplied with 24V

(c) To what accuracy can the velocity be determined?


Right (a) is simple:

Resolution = smallest distance that can be measured = linear travel of the tape per revolution divided by the number of pulses per revolution

Circumference = pi x 31.827 = 100mm

Therefore, Resolution = 100 ÷ 500 = 0.2mm per pulse

For (b) I had to use the Motor speed vs. voltage graph that we had to create as part of the experiment. I ended up with a value of 1608.56 rev/min which is 28.009 rev/s, so:

28.009 rev/sec x 100e-3m = 2.8009 m/s

But on (c) I am stuck. It's not very clear what he is asking. I think he means what is the smallest deviation from 2.8009 m/s that the encoder can measure.

Is the answer along the lines of:

If the counter/timer can't count in fractions of 1Hz (and that's merely an assumption) then surely it couldn't measure 28.009 rev/sec...so you need to find the number of rev/sec closest to 28.009 that it can measure and double it to give a tolerance band?
 
Last edited:
Physics news on Phys.org
Ping upwards
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
8K
  • · Replies 28 ·
Replies
28
Views
6K
Replies
3
Views
2K
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
37K
  • · Replies 6 ·
Replies
6
Views
5K