Question: Two electrons are fired at 3.5 x 10^6 m/s directly at each other. (a) Calculate the smallest possible distance between the two electrons. Attempt: I tried Ee=Ek for this question and this is how it went. Note*(q1=q2) Ee=Ek kq^2 = 0.5mv^2 r r= kq^2 0.5mv^2 = (9.0x10^9(N x m^2)/C^2)(1.6x10^-19C)^2 0.5(9.1x10^-31kg)(3.5x10^6m/s)^2 = 4.1x10^-11m I don't seem to be getting the right answer. Can someone please tell me what I'm doing wrong?