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BlueCardBird
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Homework Statement
Two electrons are fired at 3.5x10^6 m/s directly at each other
a) calculate the smallest possible distance between the 2 electrons
me=9.1x10^-31 Ve1=3.5x10^6 m/s qe=1.6x10^-19 C
Homework Equations
Em1=Em2
The Attempt at a Solution
Tried using Em1=Em2 which 1/2meve1^2+kqeqe/r1=1/2meve2^2+kqeqe/r2
I can't seem to use that formula because both electrons are moving, instead of one being stationary.