Calculate the time constant (RC circuit)

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Homework Help Overview

The discussion revolves around calculating the time constant in an RC circuit, focusing on the configuration of resistors and capacitors. Participants are exploring how to determine the total resistance in the circuit, which affects the time constant calculation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify whether to use a single resistance or the combined resistance for the time constant calculation. There are discussions about the arrangement of resistors in series and parallel, and how this impacts the total resistance.

Discussion Status

Some participants have provided guidance on calculating the total resistance using series and parallel rules. Others are questioning the assumptions made about the circuit configuration and the implications for the time constant. Multiple interpretations of the problem are being explored without a clear consensus.

Contextual Notes

There are indications of confusion regarding the circuit diagram and the representation of resistors and capacitors. Participants are also navigating through the limitations of their drawings and the clarity of the problem setup.

hellraiser
Hi.
How am I supposed to calculate the time constant for the enclosed circuit diagram.
I know time constant t = 1/RC
In this case do i take only one resistance or the combined value (series value)
Assume any values. I only want to understand how it is to be done.

PS: Sorry for the stupid drawing. I used MSPAINT to draw it. I think I should have practised drawing more as a kid. :)
 

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I can't see the picture but as far as I know you use the combined resistance of the timing circuit using the rules for the sumation of parallel and series resistances.
 
Ok i will try to draw it in ASCII.
__res______
| | |
| | |
bat cap res
| | |
|____|____|
res is resistor
cap is capacitor
bat is battery (+ve terminal up)
 
Obviously I failed :(
 
If I guessed right, the resistor is on the top line between the battery and the capacitor and the resistor is on the leg to the right of the capacitor??
 
Yes. You got it right.


Why is the attachment not being cleared. It's been nearly 24 hrs since I posted it. Anyone listening?
 
So now you calculate the total resistance of the circuit. Remember one is in parallel while the other is in series.
 
How? Could you show me?
I know R(series) = R1 + R2
R(parallel) = 1/R1 + 1/R2
 
Correct. You want to know the resistance acting through the capacitor. Think about it logically, if one resistor is in series with the capacitor and one is in parallel with it then could you write an equation of the total resistance acting through the circuit base on what you just said?
 
  • #10
I don't know how? Should I apply Ohm's Law and solve for an expression with time variation of current? But that would be quite lengthy.
 
  • #11
No. Simply use [tex]R_{total} = R_{series} + \frac{1}{R_{parallel}}[/tex]
 
  • #12
So the ans is R1 + R2 + (R1*R2)/(R1+R2)
 
  • #13
Ive given you the answer to calculate the total resistance above.
 
  • #14
I'm doing the same problem--how did you get that expression for Rtotal?
 
  • #15
andrewjohnsc said:
I'm doing the same problem--how did you get that expression for Rtotal?

Witchcraft or maybe prayer?:rolleyes:

Let the battery have emf Vo, and label the resistors R and r.

Answer these simple questions:

a) When Vc = 0, what is Ic?

b) When Ic = 0, what is Vc?

How long would it take the current in a) (if it stayed constant)
to charge (hint!) the capacitor C to the voltage in b)?
This is the time constant.

David
 
Last edited:
  • #16
Here's a better presented problem.
(Ignore the random stabs at answers)

Having said that, the first question should read:

1) Determine the current in each resistor and charge on the capacitor
immediately after the switch is closed


https://www.physicsforums.com/showthread.php?t=312098

In addition to what you are asked for, answer this:

What is the time constant during the charging process (switch closed)?
 
Last edited:
  • #17
Let R1 is R series and R2 is the resistance in parallel with capacitor. You can interchange R2 and C with affecting the circuit diagram. At the instant the switch is on, the voltage across R2 is E*R2/(R1 + R2). This voltage charges the capacitor. There is no resistance in series with the capacitor. Since the time constant t = RC ( not 1/RC as you have mentioned.) and R = 0 , the time constant is zero.
 

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