Calculate the time constant (RC circuit)

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hellraiser
Hi.
How am I supposed to calculate the time constant for the enclosed circuit diagram.
I know time constant t = 1/RC
In this case do i take only one resistance or the combined value (series value)
Assume any values. I only want to understand how it is to be done.

PS: Sorry for the stupid drawing. I used MSPAINT to draw it. I think I should have practised drawing more as a kid. :)
 

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Ok i will try to draw it in ASCII.
__res______
| | |
| | |
bat cap res
| | |
|____|____|
res is resistor
cap is capacitor
bat is battery (+ve terminal up)
 
Yes. You got it right.


Why is the attachment not being cleared. It's been nearly 24 hrs since I posted it. Anyone listening?
 
How? Could you show me?
I know R(series) = R1 + R2
R(parallel) = 1/R1 + 1/R2
 
Correct. You want to know the resistance acting through the capacitor. Think about it logically, if one resistor is in series with the capacitor and one is in parallel with it then could you write an equation of the total resistance acting through the circuit base on what you just said?
 
I don't know how? Should I apply Ohm's Law and solve for an expression with time variation of current? But that would be quite lengthy.
 
I'm doing the same problem--how did you get that expression for Rtotal?
 
andrewjohnsc said:
I'm doing the same problem--how did you get that expression for Rtotal?

Witchcraft or maybe prayer?:rolleyes:

Let the battery have emf Vo, and label the resistors R and r.

Answer these simple questions:

a) When Vc = 0, what is Ic?

b) When Ic = 0, what is Vc?

How long would it take the current in a) (if it stayed constant)
to charge (hint!) the capacitor C to the voltage in b)?
This is the time constant.

David
 
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Here's a better presented problem.
(Ignore the random stabs at answers)

Having said that, the first question should read:

1) Determine the current in each resistor and charge on the capacitor
immediately after the switch is closed


https://www.physicsforums.com/showthread.php?t=312098

In addition to what you are asked for, answer this:

What is the time constant during the charging process (switch closed)?
 
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Let R1 is R series and R2 is the resistance in parallel with capacitor. You can interchange R2 and C with affecting the circuit diagram. At the instant the switch is on, the voltage across R2 is E*R2/(R1 + R2). This voltage charges the capacitor. There is no resistance in series with the capacitor. Since the time constant t = RC ( not 1/RC as you have mentioned.) and R = 0 , the time constant is zero.