Calculate the velocity of the canoe relative to the water

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SUMMARY

The discussion centers on calculating Tessa's velocity relative to the ground using her velocity relative to the water, which was determined to be 4.4 m/s at N35°E. The problem requires vector addition to find the east-west components of her velocity. Participants suggest decomposing the current into its components to simplify the calculation. The importance of understanding constant velocity in relation to varying current conditions is emphasized.

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waltssillyhat
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Homework Statement
Tessa is canoeing across a river with a current of 2.5 m/s to the west.

a) Her resultant velocity (relative to the ground) is 3.6 m/s north. Calculate the velocity of the canoe relative to the water.

b) The current increases to 3.1 m/s west, but Tessa continues with the same velocity relative to the water. What is her resultant velocity relative to the ground?
Relevant Equations
Relative motion calculation
I calculated part a of the question and I found the correct solution, which was 4.4m/s N35degE, but I don't understand how to find Tessa's velocity relative to the ground in part b using her velocity relative to the water which I found in part a.
 
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The same concepts are required for both parts of the problem. Part b) should be another vector addition.

Note that there is a quick way by decomposing the new current into the old current plus the increase. But, perhaps, you should do it the standard way first.
 
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Let's see your work for part (a).
 
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IMG_2858.jpeg

sorry the photo is flipped to the side for some reason
 
In part (a), what are the components of her velocity relative to the water (taking east as positive and west as negative)?

In part (b), what is the east-west component of her velocity relative to the water and relative to the ground?
 
waltssillyhat said:
why did you draw that red curved line?
Because the problem tells us that Tessa is rowing at a constant speed respect to the water for any circumstances.
That circle represents the many directions that a velocity vector (VTR) of that magnitude could take.

That direction would be perfectly vertical and pointing North if the velocity of the current respect to ground was zero (VR=0).

That direction would be perfectly horizontal and pointing East if the velocity of the current respect to ground was equal or greater than your calculated VTR.
 
Lnewqban said:
Because the problem tells us that Tessa is rowing at a constant speed respect to the water for any circumstances.
It's a constant velocity. I don't understand the circle.
 

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