Calculate the velocity of the projectile

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To calculate the velocity of a projectile at a height of 10 m with an initial velocity of 100 m/s and g=10 m/s², the correct approach involves using the equations for horizontal and vertical components of velocity. The initial vertical velocity should be expressed as Vy² = Vi²(sin(a))² - 2gy, correcting the dimensional error in the original equation. The resultant velocity can then be calculated using Vr = sqrt(Vi² - 2gy). This method ensures accurate results by properly accounting for the effects of gravity on the vertical motion. The discussion emphasizes the importance of dimensional correctness in physics equations.
Fadi A.Saif
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Homework Statement


A stone was thrown with initial velocity of 100 m/s. Calculate the velocity of the projectile at 10 m of height. (Consider g=10m/s^2, and neglect the effect of air molecules)


Homework Equations



where's the error in the following sollution?


The Attempt at a Solution


Vr= sqrt((Vx)^2+(Vy)^2)...(1) (Resultant velocity).
Vx= Vi cos(a)...(2)
Vy=Vi sin(a)+(-2gy)...(3)
sub. (2)& (3) in (1)
Vr = sqrt(Vi^2 (cos(a))^2+Vi^2 (sin(a))^2+(-2gy)); taking Vi as a common factor, and sqrt of both sides; we get
Vr = sqrt(Vi^2-2gy) then we proceed by applying the given data from the problem
 
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The error is right here

Vy=Vi sin(a)+(-2gy)

This equation is not dimensionally correct.
 


Thanks Kuruman... so I believe it should be like this
Vy^2= Vi^2 (sin(a))^2 - 2gy.
 


That's more like it.
 

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