Calculate the Vertical Acceleration

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The discussion focuses on calculating the vertical acceleration of a 70-lb cylinder in two scenarios, emphasizing the differences in acceleration due to the presence of a 122-lb force. The user successfully calculates the acceleration for part b as 23.92 ft/s² but struggles with part a, initially thinking both cases were identical. Clarification is provided that the acceleration of the 122-lb block affects the tension in the cable, which in turn influences the 70-lb block's acceleration. It is noted that the tension is consistent on both sides of the cable, allowing for the establishment of two equations with two unknowns. Understanding the interaction between the blocks is crucial for solving the problem accurately.
Northbysouth
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Homework Statement


Calculate the vertical acceleration a (positive if up, negative if down) of the 70-lb cylinder for each of the two cases illustrated. Neglect friction and the mass of the pulleys.

I have attached an image of the problem

Homework Equations





The Attempt at a Solution



I think I've managed to calculate part b:

ƩFy = may = 122lbf - 70lbf

ay = (122lbf - 70lbf)/(70/32.2)

ay = 23.92 ft/s2

But I'm unsure with part a. Initially I has thought they were the same scenario, but after looking at the practice example (the same scenario with the final answers but the numbers are different) I can see that ay is different in both scenarios. I can see how in situation a that the 122 lb force has an acceleration which is not present in situation b but I don't see how the the acceleration in the 122 lb block would impact the 70 lb block.

Help is appreciated
 

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Northbysouth said:
I can see how in situation a that the 122 lb force has an acceleration which is not present in situation b but I don't see how the the acceleration in the 122 lb block would impact the 70 lb block.
You could think of it as the 122lb mass is 'using' some of the 122lbf acting on it for its own acceleration. So it is not all transmitted through the cable.
Let the tension in the cable be T. This is the same both sides (yes?). The acceleration is also the same both sides. That gives you two equations with the same two unknowns.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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