Calculate Time Difference: Tim vs. Rick Running and Walking

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Tim and Rick embark on a journey of distance D, with Tim walking half the time and running the other half, while Rick walks half the distance and runs the other half. The time taken by Tim is calculated as t_T = ((D/2)/v_w) + ((D/2)/v_r), while Rick's time is t_R = 2D/(v_w + v_r). To find the time difference, Delta t, Tim's time must be subtracted from Rick's time, as Tim completes the journey faster. Simplifying the equations involves using the formula for time and recognizing the average speed concept. The key takeaway is to correctly express Delta t in terms of v_r, v_w, and D, ensuring proper algebraic manipulation.
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Tim and Rick both can run at speed v_r and walk at speed v_w, with v_r greater than v_w. They set off together on a journey of distance D. Rick walks half of the distance and runs the other half. Tim walks half of the time and runs the other half.

the time it takes tim to cover the distance is:
t_R =((D/2)/v_w)+((D/2)/v_r)

the time it takes rick to cover the distance is:
t_T =2*D/(v_w+v_r)

In terms of given quantities, by what amount of time, Delta t, does Tim beat Rick?
It will help you check your answer if you simplify it algebraically and check the special case v_r = v_w.
Express the difference in time, Delta t in terms of v_r, v_w, and D.

this is an easy problem because all i need to do is take the Rick's time minus Tim's time right? I've done it and my answer is incorrect.
 
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You would take tim's time minus rick's time since tim takes less time. After that it is just algebra. All you have to do is simplify it.
 
Parth Dave said:
You would take tim's time minus rick's time since tim takes less time. After that it is just algebra. All you have to do is simplify it.


that's my problem. i couldn't simplify it correctly. i simplified it to be

(2D(VwVr)-D/2(Vr+Vw)(Vw+Vr))/((Vw+Vr)(VwVr))
but this is not the answer
 
A. use the formula d=v/t and rearrange it for time to t=d/v, since you have two v values (v_r and v_w), change the equation to t= (d/2vw)+(d/2vr). The two is in there because you multiple the distance by (1/2) which puts the two into the denominator.
B. The average speed is found by rearranging the answer to the above equation to answer for vw+vr, instead of time. You don't have to separate vw+vr when you get it on to the left side.
E. you DO have to subtract tims time from ricks because even though tim finishes first, rick takes LONGER thus a greater value for time. (or time would be negative otherwise)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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