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yeahman68

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A man is running and walking a distance of 2 km. He will walk for 1 km and run for 1 km. At the end, his average velocity was recorded to be 15 km/hr. His running velocity is twice that of his walking velocity. What was his walking speed?

The answer was recorded to be 7.5 km/hr, but cannot figure it out unfortunately.

This is how I attempted to do the problem:

Equation relating the two velocities: time = 1/2(Distance/Velocity of walking) + 1/2(Distance/Velocity of running)

Average Velocity=Total Distance/Total Time

15 km/hr= 2 km / x hours x= (2/15) hr or (.1333333333 hr)

Tried doing things past this point but cannot get the correct answer.

The answer was recorded to be 7.5 km/hr, but cannot figure it out unfortunately.

This is how I attempted to do the problem:

Equation relating the two velocities: time = 1/2(Distance/Velocity of walking) + 1/2(Distance/Velocity of running)

Average Velocity=Total Distance/Total Time

15 km/hr= 2 km / x hours x= (2/15) hr or (.1333333333 hr)

Tried doing things past this point but cannot get the correct answer.

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