Calculate velocity in a "simple electric train"

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raymondd
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Homework Statement
How do you calculate the velocity of the battery with 2 magnets attached on polar ends moving in a coiled copper wire
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How do you calculate the terminal velocity of the train moving in a coiled copper wire with two magnets attached to the polar ends?
I have attached someone else's work I've found on the internet here and need help Handwritten derivation of terminal velocity for a dipole moving through a coil: Eddy current I_E = 2e1/R_T = -c v/R_i, net force F = cI + cI_E, terminal velocity v = I_E R_T / c, then v = V/c with V = battery voltage.Handwritten derivation titled "Velocity with which train is Moving" computing the EMF of a moving dipole loop: flux integral of B·dA, x(t) = x - vt, and a double integral with dB/dx and mu0 Nm terms, ending in e1 = -1/2 v e.Photo of a homemade simple electric train: a battery lying on a wooden surface, with copper wire coiled at both ends and bent into a loop behind it. Label reads GP Super Alkaline 910A LR1 1.5V.