Calculate Volume of 24NaI Stock Solution for 1kBq at 8:30am on 4th June

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SUMMARY

The discussion focuses on calculating the volume of a 24NaI stock solution required to achieve an activity of 1 kBq at 8:30 AM on June 4th, given that the half-life of 24Na is 15 hours and the initial activity was 16,000 Bq in 25 cm³ at 5:00 PM on June 2nd. Participants emphasize the importance of using the half-life and exponential decay equations to determine the remaining activity over time. The problem-solving approach involves applying the decay constant derived from the half-life to find the necessary volume of the stock solution.

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Homework Statement


The Half life of the isotope 24Na is 15.00 hours. a stock solution of 24NaI contained 16000Bq of activity in 25cm3 at 5.00 pm on the 2nd of june. An experiment starting at 8:30am on the 4th of june requires 1kBq. What volume of the stock 24NaI solution would be required to give the desired activity at 8:30 am on the 4th of june

Homework Equations



I am not given any equation but the ones that relate to it are the simple half life, decay constant and exponential decay equations

The Attempt at a Solution


I really have no idea where to start in this problem i know this is asking a lot but any indication or support would be greatly appriciated
 
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welcome to pf!

hi roley! welcome to pf! :wink:
roley said:

Homework Equations



I am not given any equation but the ones that relate to it are the simple half life, decay constant and exponential decay equations

ok, write out these equations, and we'll take it from there :smile:
 

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