Calculating Stock Solution Volume for NaHCO3 5g/L: M1V1=M2V2

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SUMMARY

The discussion focuses on calculating the stock solution volume required to prepare a 100 mL NaHCO3 solution at a concentration of 5 g/L using a stock solution of NaHCO3 at 30 g/L. The relevant equation used is M1V1 = M2V2, where M1 is the molarity of the stock solution, V1 is the volume of the stock solution needed, M2 is the desired molarity, and V2 is the final volume. The correct calculation shows that to achieve the desired concentration, 3.33 mL of the 30 g/L stock solution is required, not 16.7 mL as initially calculated. The final solution must contain 0.5 g of NaHCO3, which is derived from the dilution of the stock solution.

PREREQUISITES
  • Understanding of molarity and its calculation.
  • Familiarity with the dilution equation M1V1 = M2V2.
  • Basic knowledge of grams per liter (g/L) concentration.
  • Ability to perform unit conversions and basic algebra.
NEXT STEPS
  • Review the concept of molarity and how to calculate it for different solutes.
  • Practice using the dilution equation M1V1 = M2V2 with various concentrations.
  • Explore the implications of concentration in solution preparation for laboratory settings.
  • Learn about the properties and applications of sodium bicarbonate (NaHCO3) in chemical solutions.
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in solution preparation and dilution calculations.

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Homework Statement


Whats the stock solution volume required to prepare 100ml of a NaHCO3 solution 5g/L using a stock solution of NaHCO3 30g/L.

Homework Equations



M1*V1 = M2*V2

M = Molarity = mols/L

The Attempt at a Solution



NaHCO3 = 84g/mol
5g NaHCO3 = 0.0595238095238095mol
30g NaHCO3 = 0.3571428571428571mol

M1*V1 = M2*V2 => 0.0595238095238095*0.1 = 0.3571428571428571*V2
V2 = 0.01666L = 16,7mL

But the answer is 3,33 mL
 
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16.7 mL is the right answer.

Note: there is no need to convert everything to moles and molar concentrations. Answer doesn't depend on the identity of the substance. Final solution must contain 0.5 g (0.1L*5g/L), so you need to start with 0.5g/30g liters of the stock solution and dilute it to 100 mL.
 

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