Calculate ∫∫x^2 dS of Triangle

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Homework Help Overview

The problem involves calculating the double integral ∫∫x^2 dS over a triangular region defined by the vertices (1,1,0), (0,1,0), and (0,0,1). The triangle is described as the graph of the function g(x,y) = 1 - x - y.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss two different integrals that represent the same area but yield different results. There is a focus on the integrand and the implications of changing the order of integration.

Discussion Status

Some participants are questioning the consistency of the integrand when changing the order of integration, while others are clarifying the geometric interpretation of the triangular region involved in the problem.

Contextual Notes

There is mention of potential confusion regarding the integrand and limits of integration, as well as the geometric representation of the triangle in the context of the problem.

bugatti79
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Homework Statement



Calculate ∫∫x^2 dS where S is the triangle with corners (1,1,0) (0,1,0) and (0,0,1)

The triangle is the graph of g(x,y)=1-x-y

One integral can be \displaystyle \sqrt3 [\int_{0}^{1}(\int_{0}^{1-x}x^2dy)dx]

I calculate the other one to be

\displaystyle \sqrt3 [\int_{0}^{1}(\int_{0}^{1-y}(1-y)^2dx)dy]

but I don't get the same answer...can some one point it out?

Thanks
 
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bugatti79 said:

Homework Statement



Calculate ∫∫x^2 dS where S is the triangle with corners (1,1,0) (0,1,0) and (0,0,1)

The triangle is the graph of g(x,y)=1-x-y

One integral can be \displaystyle \sqrt3 [\int_{0}^{1}(\int_{0}^{1-x}x^2dy)dx]

I calculate the other one to be

\displaystyle \sqrt3 [\int_{0}^{1}(\int_{0}^{1-y}(1-y)^2dx)dy]

but I don't get the same answer...can some one point it out?

Thanks

The integrand, x2, should not change when you change the order of integration.
 


Mark44 said:
The integrand, x2, should not change when you change the order of integration.

OK, thanks. I am wondering did I come across situations where one does change the integrand or perhaps I am confusing it with changing the limits when there is a u substitution involved etc?

thanks
 


I'm pretty sure the triangle is in the plane, y+z = 1 .
 

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