Calculate x^33 Coefficient: Binomial Theorem

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To find the coefficient of x^33 in the expansion of (1/4 - 2x^3)^17 using the binomial theorem, the term involving x^33 requires that x^3 be raised to the power of 11, since 3 times 11 equals 33. The relevant binomial coefficient is calculated as C(17, 11), which represents the number of ways to choose 11 instances of x^3 from the 17 total terms. The coefficient for this term is then determined by multiplying C(17, 11) by (-2)^11, as the term includes a factor of -2 from the binomial expansion. The final coefficient of x^33 is thus C(17, 11) * (-2)^11, confirming that the approach to find the coefficient is correct. This method effectively utilizes the binomial theorem to solve the problem.
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use the binomial theorem to determine the coefficient of x^33 in the expansion of (\frac{1}{4}-2x^3)^17

ive played around with it and come up with 33^C_17
as a coefficient.am i right in saying that is all the question asks

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You have to find x^33 so the x term should be raised to 11. Cause your x term is x^3 and X^3 power 11 is x^33
 
so is that like 2-11^C_1(x)3 +11^C_2(x)^4 +11^C_3(x)^5 and so on.
 
it would x^3, x^6,x^9 so on
 
in my book it has the largest power on the ^C of C and then the other lower case, is powered up to the sequence it is. in the X^ 3 so the x^3 then x^6 x^9 .what would the largest be the 33 or the 11.

i was thinking the sequence would start at the x^3
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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