Calculating acc. from the given data

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SUMMARY

The discussion focuses on calculating the acceleration of a car that covers 450 meters in the first 5 seconds and 700 meters in the subsequent 5 seconds. The initial approach of calculating average velocities (90 m/s and 140 m/s) is incorrect for determining acceleration. Instead, participants suggest using two constant acceleration equations for each time interval to accurately compute the acceleration. The correct method involves applying kinematic equations to account for the change in velocity over time.

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Homework Statement



A car moving with uniform acceleration covers 450m in a 5 second interval, and covers 700m in the next 5 seconds interval. The acceleration of the car is ?

Homework Equations





The Attempt at a Solution



please correct me if i am wrong, i calculate velocity at the end of the first run i.e. v1= 450/5= 90m/s . And then at the end of 2nd run v2= 700/5 = 140 m/s. Then i apply,
Acceleration =change in velocity upon time period i.e. (140-90)/5 = 10m/s^2 , right?
Thank you.
 
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hi jatin1990! :smile:
jatin1990 said:
please correct me if i am wrong, i calculate velocity at the end of the first run i.e. v1= 450/5= 90m/s . And then at the end of 2nd run v2= 700/5 = 140 m/s.

nooo, that gives you the average velocity, which doesn't help much :redface:

you'll probably need two constant acceleration equations, one for each time period

(you may find it easier to put t = 0 in the middle, so that the two end-times are ±5 s :wink:)
 

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