Calculating acceleration and brake force

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SUMMARY

The discussion focuses on calculating the average force exerted by the brakes of a car with a mass of 600 kg, initially traveling at 45 m/s, which comes to rest over a distance of 12 m. The relevant equations used are Force = mass x acceleration and V² = u² + 2as. The correct approach to find acceleration involves rearranging the equation to a = (v² - u²) / (2s), leading to an acceleration of -168.75 m/s². This value is then used to calculate the average braking force as 1012.5 N.

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cyberhev
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Homework Statement

Hi all, the question for revision is; A car of mass 600kg traveling at 45m/s comes to rest in 12m when the brakes are applied. What is the average force exerted by the brakes?

Homework Equations

Force = mass x acceleration V^2=u^2 +2as

The Attempt at a Solution

I know I need to work out the acceleration but am having trouble correctly transposing that equation I think its this v^2-u^2 divided by s =2a, its what to do with the 2 to get a on its own, does it then become 1/2 s on the other side?
 
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cyberhev said:

Homework Statement

Hi all, the question for revision is; A car of mass 600kg traveling at 45m/s comes to rest in 12m when the brakes are applied. What is the average force exerted by the brakes?



Homework Equations

Force = mass x acceleration V^2=u^2 +2as



The Attempt at a Solution

I know I need to work out the acceleration but am having trouble correctly transposing that equation I think its this v^2-u^2 divided by s =2a, its what to do with the 2 to get a on its own, does it then become 1/2 s on the other side?

You're using the correct equation, but it looks like you need some help in "solving for a" to get the acceleration.

Let's write out what you correctly have so far:

<br /> \frac{v^2-u^2}{s}=2a<br />

Hopefully that helps you see better what to do ... if not, then post again.

p.s. I'm not quite sure if
1/2 s
means "(1/2)s" or 1/(2s).
 
That is what i have so far, I am just not sure where the 2 goes so you just get a on its own, I was wondering the 2 then moves to the side of s to become1/2s.
 
If I solve that equation with 2a. I did the following 45x45-0x0, divided by 12 = 168.75 x 2 =337.5. Is this the correct acceleration?
 
\frac{v^2-u^2}{s}=2a

\Rightarrow \frac{v^2-u^2}{2s}=a
 
Yes I have it, thank you, my transposition of equations knowledge is in there, but its 15 years or so since I used it! I often write the suvat list out, i find it very helpful.
 

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