Calculating Acceleration Due to Gravity Using Velocity, Time, and Position Data

AI Thread Summary
The discussion revolves around calculating the acceleration due to gravity using collected data on velocity, time, and position. Participants emphasize that while the known value of gravity is -9.81 m/s², the lab requires students to derive this value from their data. They suggest graphing velocity versus time to find the slope, which represents acceleration, and discuss the importance of understanding initial conditions and forces acting on the object. Confusion arises regarding the application of equations for motion, particularly when integrating them to find displacement and acceleration. Ultimately, participants encourage sharing experimental data for further clarification and troubleshooting.
ejohnston
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Homework Statement


I was given a lab using the logger lite and go motion probe. After collecting my data, which is only velocity, time and position, i was asked to calculate the acceleration due to gravity. We have never gone over this and the only information i have is to due with what i said before.
We do know that acceleration is -9.81 though

Homework Equations


Is there anyway to find out the acceleration due to gravity for this ! I don't understand how i am suppose to find this out !


The Attempt at a Solution

 
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If acceleration is constant, then v = at. Try graphing the velocity versus time and looking for the slope.
 
ejohnston said:

Homework Statement


I was given a lab using the logger lite and go motion probe. After collecting my data, which is only velocity, time and position, i was asked to calculate the acceleration due to gravity. We have never gone over this and the only information i have is to due with what i said before.
We do know that acceleration is -9.81 though

Homework Equations


Is there anyway to find out the acceleration due to gravity for this ! I don't understand how i am suppose to find this out !


The Attempt at a Solution


For a lab, remember that you don't "know" gravity is -9.81 \frac{m}{s^2} since that is what you are told to find.

In the most basic sense, what is acceleration? Try listing a few different ways to describe acceleration (i.e. different equations).

After making the list (make sure you show units in your descriptions), can you use anything from your data to construct this?
 
daveb ! thank you for replying so fast ! but my v-t graph has multiple places to find the sole. it starts at 0, accelerates up, then de-celerates ! where do i find my slope?
 
Ignea_unda said:
For a lab, remember that you don't "know" gravity is -9.81 \frac{m}{s^2} since that is what you are told to find.

In the most basic sense, what is acceleration? Try listing a few different ways to describe acceleration (i.e. different equations).

After making the list (make sure you show units in your descriptions), can you use anything from your data to construct this?

that is what i ended up doing, yet i found an exceleration of -1.04m/s2 ! urg that means the percent error is 89! does that even make sens if the ball i threw in the air was a volly ball ?
 
daveb; v(t)=at+v0. The constant is actually important, if this isn't a simple freefall-experiment that is.

integrating this equation with time yields, s(t) = 0,5at^2 + v0*t.
if you know the initial velocity, the time the journey took and how long it travelled, can't you solve for a?
 
ejohnston said:
daveb ! thank you for replying so fast ! but my v-t graph has multiple places to find the sole. it starts at 0, accelerates up, then de-celerates ! where do i find my slope?

Think about where the ball was at each point in time. After it leaves your hands, what forces are acting on it? I don't think that after it left your hand it was accelerating up, but rather just had a positive velocity at that time.
 
Cipherflak said:
daveb; v(t)=at+v0. The constant is actually important, unless you do a simple freefall-experiment

integrating this equation with time yields, s(t) = 0,5at^2 + v0*t.
if you know the initial velocity, the time the journey took and how long it travelled, can't you solve for a?

this is what i have been looking for! but my teacher hasn't explained what s(t) = 0,5at^2 + v0*t means -_- would you mind explaining this to me?
 
it as an equation that describes how long your object travels, s, when you plug in acceleration and time. and initial velocity, v0. :)

Or did you ask how I got there?
 
  • #10
Cipherflak said:
it as an equation that describes how long your object travels, s, when you plug in acceleration and time. and initial velocity, v0. :)

Or did you ask how I got there?

Thank you :) but now when rearanging my eqation, i have 2 t, do i replace both with the same number ?!
 
  • #11
first of all, what is your initial velocity? if you simply "dropped" the ball, it is 0 and you lose a term.
 
  • #12
Cipherflak said:
first of all, what is your initial velocity? if you simply "dropped" the ball, it is 0 and you lose a term.

no, the ball was thrown then catched, but i see what you're saying , so my v1 is 0, v2 0.157 m and time is 1.8s so the acceleration is 1.045 m/s^2 ? ahh so confusing!
 
  • #13
no matter. you get one term of t^2 and one term of t, but this pose no problem. As far as I've understood you are solving for a, and the value of t is known?

if it doesn't work, give me all your experimental data and explain what you did in the lab.
 
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