Determining Acceleration due to gravity using a Spring

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SUMMARY

This discussion focuses on determining the acceleration due to gravity (g) using a helical spring. The user calculated the extension of the spring (x) for various loads (L) and plotted graphs for L vs x and L vs T², where T is the time period for oscillations. The derived formula for calculating g is $$g= 4 \pi ^2 \frac {Slope \; of \; L \; vs \; T^2 \; graph}{Slope \; of \; L \; vs \; x \; graph}$$, leading to a calculated value of g = 10 m/s². The user seeks validation of the formulas and the process used for these calculations.

PREREQUISITES
  • Understanding of Hooke's Law and spring mechanics
  • Basic knowledge of oscillation and time period calculations
  • Familiarity with graphing and slope determination
  • Knowledge of gravitational acceleration concepts
NEXT STEPS
  • Review the derivation of the formula $$ T = 2\pi \sqrt {\frac {x}{g} } $$
  • Explore advanced spring dynamics and oscillation theory
  • Learn about experimental methods for measuring gravitational acceleration
  • Investigate the impact of mass and spring constant on oscillation frequency
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Physics students, educators, and researchers interested in experimental mechanics and gravitational studies will benefit from this discussion.

Wrichik Basu
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I want to determine the acceleration due to gravity at a place using a helical spring.

For this, I've first calculated the extension in length of the spring (##x##) for a particular load (##L##) on the pan. Then I've plotted a graph for ##L## vs ##x## for different values of L and corresponding values of ##x##, and calculated it's slope.
Next, I've calculated the time period for 20 oscillations of the spring for each of the weights I've used before. I've calculated the time period for one oscillation, and taken the average of 3 readings (##T##). I've plotted a graph for ##L## vs (##T ^2 ##), and calculated it's slope.
I've used this formula for the calculation of acceleration due to gravity: $$g= 4 \pi ^2 \frac {Slope \; of \; L \; vs \; T^2 \; graph}{Slope \; of \; L \; vs \; x \; graph} $$ which I derived from the formula $$ T = 2\pi \sqrt {\frac {x}{g} } $$ from where we can get $$\begin{align} g = 4 \pi ^2 \frac {x}{T ^2} \nonumber \\ &= 4 \pi ^2 \dfrac {\frac {L}{T ^2}}{\frac {L}{x}} \nonumber \end {align}$$.
Are these formule correct? I've got the value of ##g=10 m/ s^2##, which seems to be approximately correct, but I wanted to know whether the process I used is correct.
 
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The second formula has x in it, which depends on L, but it doesn't have L in it. That is odd. Where does the formula come from?

The overall result looks fine.
 
mfb said:
The second formula has x in it, which depends on L, but it doesn't have L in it. That is odd. Where does the formula come from?

The overall result looks fine.
From these youtube videos:

 

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