Calculating Acceleration of 2 kg Ball on Inclined Plane

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Homework Help Overview

The problem involves calculating the acceleration of a 2 kg ball on a frictionless inclined plane set at 30 degrees to the horizontal. The context includes considerations of forces acting on the ball, including gravitational force and the normal force.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss drawing force diagrams and rotating coordinate systems to analyze forces. Questions arise regarding the acceleration components in the new coordinate system and the implications for force balance in the y-direction.

Discussion Status

Some participants have provided guidance on modeling the ball as a point mass and clarifying the distinction between forces and acceleration. There is recognition of potential issues with the problem setup, particularly regarding the nature of the object (ball vs. block) and the implications of rolling versus sliding.

Contextual Notes

Participants note the absence of friction and the lack of information regarding the radius of the ball, which raises questions about the assumptions made in the problem. There is acknowledgment of possible oversight in the problem's framing.

Pupil
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Homework Statement


An inclined plane is 30 degrees above the horizontal with a 2 kg ball at the top. Assume no friction or air resistance, and assume acceleration due to gravity is 10 [m/s^2]. Find the acceleration of the ball in the vertical and horizontal.

Homework Equations


F = ma

The Attempt at a Solution


So my attempt at the problem is to draw a force diagram of the situation, and then rotate my axis so that the normal force points up, and the gravitational field force points 30 degrees left, like this: http://img49.imageshack.us/my.php?image=yghrtqi6.jpg

So after that it's pretty easy to find the x and y components of Fg (since I know the hypotenuse is 20 N), but how do I find Fn?
 
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Under your new coordinate system does the ball have any acceleration in the y component? What does that answer suggest about the forces in the y direction?
 
jgens said:
Under your new coordinate system does the ball have any acceleration in the y component? What does that answer suggest about the forces in the y direction?

Oh, I see! Since the coordinate system has been shifted 30 degrees the acceleration now points exactly in the x direction; this means the acceleration in the y-direction is 0. The y forces must balance (Fgy = -Fn), so the acceleration is just Fgx. Thanks!
 
there's a problem, i suggest. We are considering a ball not a block and hence we must consider pure rolling.But there is no radius given. So may be there is a problem with the question
 
FedEx said:
there's a problem, i suggest. We are considering a ball not a block and hence we must consider pure rolling.But there is no radius given. So may be there is a problem with the question
Yes, a bit strange that they used a ball instead of block, but no matter. Since there's no friction, the ball will slide not roll. (Probably just an oversight.)

If the ball did roll, then the acceleration would be different. But it would not depend on the radius.
 
Doc Al said:
Yes, a bit strange that they used a ball instead of block, but no matter. Since there's no friction, the ball will slide not roll. (Probably just an oversight.)

If the ball did roll, then the acceleration would be different. But it would not depend on the radius.

Oops. It would depend on radius of gyration but not radius.
 
Since there's no friction the ball will slide, not roll.
 
Guys, there is a serious lapse in my concentration. First i write radius instead of radius of gyration and second i don't even read the question properly which says " no friction"
 
Last edited:
Pupil said:
The y forces must balance (Fgy = -Fn), so the acceleration is just Fgx.

Hi Pupil, I hope you got your questions answered. If you aren't studying rotational stuff right now, I would just model the ball as a point mass for this problem. Also, don't forget that Fgx is a force, not an acceleration. You must divide out the mass to get the acceleration... Let us know if you've got it ok!
 
  • #10
korkscrew said:
Hi Pupil, I hope you got your questions answered. If you aren't studying rotational stuff right now, I would just model the ball as a point mass for this problem. Also, don't forget that Fgx is a force, not an acceleration. You must divide out the mass to get the acceleration... Let us know if you've got it ok!

Whoops! Yeah, I meant Fgx is a force (I occasionally mix my lingo when thinking about too many things at once). I think my teacher meant the ball as just some object sliding down a ramp. Thanks for the help guys!
 

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