Ball bounces several times on an inclined plane

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SUMMARY

The discussion focuses on the physics problem of a ball bouncing on an inclined plane with an inclination angle of 45° and a height of 5 m. The coefficient of restitution is given as e = 0.75. The initial solution determined the distance along the incline to be 8h sin(θ), resulting in a final distance of approximately 18.5 m after accounting for the coefficient of restitution. The participants clarified that with e < 1, the angle of reflection exceeds the angle of incidence, confirming the calculations against the textbook values.

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  • Understanding of basic physics concepts, particularly elastic collisions
  • Familiarity with the coefficient of restitution in mechanics
  • Knowledge of trigonometric functions and their applications in physics
  • Ability to solve problems involving inclined planes and projectile motion
NEXT STEPS
  • Study the principles of elastic and inelastic collisions in detail
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  • Investigate the effects of different angles of inclination on projectile motion
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for problem-solving strategies related to collisions and inclined planes.

carlyn medona

Homework Statement



A ball falls on an inclined plane of inclination theta from a
height h above the point of impact and makes a perfectly
elastic collision. Where will it hit the plane again ?
Solve the previous problem if the coefficient of restitution
is e. Use theta = 45°, e = .75 and h = 5 m.

Homework Equations

The Attempt at a Solution


I was able to solve first part of the problem and got the distance along the incline to be =8hsinθ. For second part I am getting angle of reflection of ball with normal to be 53 degree but the value in my text is 37degree. but I don't think the angle should be less than theta
 
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perfectly elastic collision
coefficient of restitution is e.
e = 0.75
So is it perfectly elastic or not?
 
yrjosmiel said:
So is it perfectly elastic or not?
They want it solved twice. Once perfectly elastic then again with e=0.75.
 
that's right. In second case it is not elatic
 
carlyn medona said:
angle of reflection of ball with normal to be 53 degree but the value in my text is 37degree. but I don't think the angle should be less than theta
You are correct. If e < 1 then the angle to the normal of the reflection will be greater than the incident angle to the normal.
I assume you noticed that 37=90-53.
 
yes.
 
okay i finally solved it and got a value of 18.5 m along the incline, thanks for the help.
 
carlyn medona said:
okay i finally solved it and got a value of 18.5 m along the incline, thanks for the help.
Good. (I get 18.56.)
 
Thank you for your help.
 

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