Calculating acceleration of a falling orange

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Homework Help Overview

The discussion revolves around calculating the acceleration of a falling orange using data from a time-position table. Participants are tasked with creating a time-velocity table and drawing a velocity-time graph based on the provided data.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about converting the time-position table into a time-velocity table and seek clarification on the process. There are discussions regarding the method of calculating instantaneous velocity, with some suggesting the use of average velocities over intervals and others calculating slopes from tangent lines.

Discussion Status

Some participants have provided guidance on how to approach the problem, including methods for calculating velocities and plotting them accurately. There is ongoing exploration of different methods and interpretations, but no explicit consensus has been reached regarding the best approach.

Contextual Notes

Participants mention issues with attachments and data clarity, indicating potential constraints in sharing information. The original poster's attempts and the nature of the problem suggest a learning environment where assumptions and methods are being questioned.

mr.plow
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Homework Statement


Using the data found in this chart, create a time-velocity table and draw a velocity-time graph. Once you have done that, calculate the acceleration of the orange as it falls to the ground. (table attached as image).

Homework Equations


I'm not even sure about this... I don't understand how to convert the time-position table into a time-velocity table, and it wasn't clearly explained in the lesson.

The Attempt at a Solution


Another attachment will show my attempt..
The time-position graph mentioned in this attempt turned out to be a 17mb jpeg, and I'm sure I didnt even need this graph to get this answer now that I look at it again... I feel like this should be a really easy solution. Any help would be GREATLY appreciated!
 
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Is the attachment showing?
 
mr.plow said:

Homework Statement


Using the data found in this chart, create a time-velocity table and draw a velocity-time graph. Once you have done that, calculate the acceleration of the orange as it falls to the ground. (table attached as image).


Homework Equations


I'm not even sure about this... I don't understand how to convert the time-position table into a time-velocity table, and it wasn't clearly explained in the lesson.


The Attempt at a Solution


Another attachment will show my attempt..
The time-position graph mentioned in this attempt turned out to be a 17mb jpeg, and I'm sure I didnt even need this graph to get this answer now that I look at it again... I feel like this should be a really easy solution. Any help would be GREATLY appreciated!

mr.plow said:
Is the attachment showing?

I'm not seeing it. Try again?
 
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OK, I guess I'll try uploading that data again. I also figured out how to compress the graph data into a .zip file. I end up getting 8.4m/s, which is strange because I don't see where I could have made an error... again, any help is so greatly appreciated.
 

Attachments

  • time-position to time-velocity table.jpg
    time-position to time-velocity table.jpg
    16.7 KB · Views: 814
  • time-position to time-velocity table.zip
    time-position to time-velocity table.zip
    56.7 KB · Views: 465
oops, zipped the wrong file, let's try this againnn hah..
 

Attachments

  • jesse's graph unit 2.jpg
    jesse's graph unit 2.jpg
    23.2 KB · Views: 747
So have you been able to make progress on the problem? The latest attachment looks like you have been able to do some graphing? (it's hard to read though...)
 
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The graphing in the latest attachment is where I got the data for the time-instantaneous velocity table for points A,B, and C by calculating the slopes for each tangent line. I was hoping that it would be more easily read from the thumbnail, but I'm new on this forum. If you open the graph in a new tab/window, you can see where I got my data from for the first thumbnail photo a little more clearly. You may have to increase the zoom on the page you view it in, but you should be able to tell if I goofed up on the slope calculations.
 
I can see what they did in the attachment. They used the data from 0.25 and 0.5 to get the average velocity over this interval. The same goes for the data from 0.75 to 1.0, and from 1.25 to 1.5. The question is, at what time should the velocity be plotted for each of these intervals, if the calculated velocity is the average over these intervals? The answer is, to get good accuracy on the instantaneous velocity, it should be plotted at the half-way point for each interval: 0.375, 0.875, and 1.375 sec. This gives "second order accuracy" on the instantaneous velocity, and is exact if the distance is varying as a quadratic with time. This is about the best you are going to do.

You used a different method, by drawing tangents to the smooth curve you drew, and taking the slope. If you plot your results and the results obtained using the method I described above, your method should agree pretty well with the results in the attachment. You can also do the calculations for the other time intervals in the table using the method I described. This will give you a more fleshed-out plot of how the instantaneous velocity versus time.

The same time of approach can be used to take the results obtained from the velocity calculations and using them to estimate the instantaneous acceleration versus time.
 
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Hi, i wanted to know if you found the answer to this question? Was the above mentioned answer of using the half way points for each interval correct?
 
  • #10
heh said:
Hi, i wanted to know if you found the answer to this question? Was the above mentioned answer of using the half way points for each interval correct?
Welcome to the PF.

This thread is from 2013, so I'm pretty sure the OP has moved on by now. :smile:
 
  • #11
heh said:
Hi, i wanted to know if you found the answer to this question? Was the above mentioned answer of using the half way points for each interval correct?

The answer is that it should have been an apple, not an orange.
 
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