Calculating acceleration offset by CG

  • Level: Graduate 
  • Thread starter Thread starter The Don
  • Start date Start date
  • Tags Tags
    Acceleration
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views · last reply
The Don
Messages
11
Reaction score
1
I'm trying to calculate the acceleration an accelerometer would read NOT placed in the Center of Gravity of the object. Let's look at the figure below. The accelerometer was placed in location (Xa,Za) and not in the CG of the object. Given that the accel's output is a_x and a_z at this location (Xa,Za)...what would've the accelerometers have read if placed on the C.G. of object?

Diagram of a paper airplane in side view with body axes x body (horizontal) and z body (downward), a centre of gravity marked as a circle, and an IMU offset point at distance Xa along x and Za along z, with angle alpha and vectors labelled sqrt(xa^2 + za^2), q, and q_dot.


Here is an attempt at the solution (http://basicairdata.blogspot.com/2014/05/inertial-measurement-unit-placement.html) however I don't fully understand how they got the transformation matrix.

How does q_dot come into play in the calculations and how does alpha (angle) disappear in the matrix?
 
Last edited:
Physics news on Phys.org