Calculating Activation Energy with Temperature and Time Data

Click For Summary
SUMMARY

The discussion focuses on calculating the activation energy (Ea) for cooking an egg at different altitudes using the formula ln(k2/k1) = (-Ea/R)((1/T2)-(1/T1)). The temperatures provided are T1 = 372.0K and T2 = 363.0K, with cooking times of 336 seconds in Houston and 270 seconds in Cripple Creek. The calculated Ea was approximately 27000 J/mol, but the user encountered discrepancies with Webassign, indicating potential roundoff errors or calculation mistakes.

PREREQUISITES
  • Understanding of the Arrhenius equation for activation energy
  • Knowledge of temperature conversion between Celsius and Kelvin
  • Familiarity with the concept of rate constants in chemical kinetics
  • Basic skills in algebra for rearranging equations
NEXT STEPS
  • Review the Arrhenius equation and its application in chemical kinetics
  • Learn about temperature conversions and their significance in thermodynamic calculations
  • Study the impact of altitude on boiling points and reaction rates
  • Explore methods to minimize roundoff errors in calculations
USEFUL FOR

Chemistry students, educators, and anyone involved in thermodynamics or chemical kinetics, particularly those interested in the effects of temperature and altitude on reaction rates.

brandon1
Messages
34
Reaction score
0

Homework Statement



In Houston (near sea level), water boils at 100.0°C. In Cripple Creek, Colorado (near 9500 ft), it boils at 90.0°C. If it takes 5.6 min to cook an egg in Cripple Creek and 4.5 min in Houston, what is Ea for this process?What I do not understand is how I can figure this when the given formula for find Ea involves 2 unknown rate constants, and the formula for finding the rate constant given involves concentrations? So, how can I find the activation energy when given only 2 temperatures and 2 times?

Homework Equations



ln(k2/k1)=(-Ea/R)[(1/T2)-(1/T1)]^-1

k=rate1/(concetrations)

The Attempt at a Solution



Not sure where to start...
 
Physics news on Phys.org
well, you have an equation for Ea... rearrange it to solve for Ea.

What variables do you know? What variables do you need?

hint: you might not have to solve for each k value individually
 
dmoravec said:
well, you have an equation for Ea... rearrange it to solve for Ea.

What variables do you know? What variables do you need?

hint: you might not have to solve for each k value individually

Ea=-R(ln k2/k1)[(1/T2)-(1/T1)]^-1

Ea=?
T2=363.0K
T1=372.0K
time1=336s
time2=270s
R=8.314 J/mol*k

Do I plug in the times for k? I am attempting it now, it looks as if it should still all cancel and leave me with J/mol which I want...
 
Ok, I came up with 27279.97791 J/mol corrected to 27000 J/mol for sig figs, but Webassign says I am wrong, and within 10% of the correct answer. "Your answer is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error."Edit: I wrote a temp incorrectly in my conversion. Correct now!
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 131 ·
5
Replies
131
Views
10K
Replies
3
Views
28K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
93K