# Find the rate constant, given temperature and activation energy.

1. Sep 18, 2010

### Agent M27

1. The problem statement, all variables and given/known data

A reaction is found to have an activation energy of 38.0 kJ/mol. If the rate constant for this reaction is 1.60 × 102 M-1s-1 at 249 K, what is the rate constant at 436 K?

2. Relevant equations

$$ln\frac{K_{2}}{K_{1}}=\frac{E_{a}}{R}\left(\frac{1}{T_{1}}-\frac{1}{T_{2}}\right)$$

3. The attempt at a solution

Given:

R=8.314
T1=249K
T2=436K
Ea=160

$$ln(K_{2})=\frac{38}{8.314}\left(\frac{1}{249}-\frac{1}{436}\right)+ln(160)$$

Which equals 161.257 which is incorrect. Any clues where I went wrong would be greatly appreciated. Thanks in advance.

Joe

2. Sep 18, 2010

### Staff: Mentor

38000

3. Sep 19, 2010

### Agent M27

Ah ha! I should have noticed that being that R has units of J not Kj. Thank you very much Borek.

Joe

4. Sep 19, 2010

### Staff: Mentor

kJ, not Kj...

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