Calculating Aircraft Displacement & Velocity

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High_Voltage
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Homework Statement



A radar station detects an aircraft (moving east to west) at 1200ft at 40degrees. 12 seconds later the plane is 2080 ft from the station and has advanced 123degrees find

His displacement

His average Velocity

Homework Equations



Dx=dx1 + dx2
Dy=dy1 + dy2

The Attempt at a Solution



Dx1=919ft Dy1=771ft

Dx2=2467ft Dy2=754ft

-3386 -17 (NEGATIVE IS THE NEGATIVE DIRECTION ON THE AXIS)

(3386^2)+(17^2)= 3386.04-(RESULTANT)

How can I find the angle please.
 
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I'm not sure which angle you want to find. You are given the angles in the question.
The plane is moving east to west so it's displacement is due west of its original position.
Could you be more specific?
Also, have you checked your answer? Is it correct?
 
High_Voltage said:
A radar station detects an aircraft (moving east to west) at 1200ft at 40degrees. 12 seconds later the plane is 2080 ft from the station and has advanced 123degrees ...

Is the plane flying due west (180 degrees)?

What does the statement "at 40 degrees" refer to? It isn't clear, as stated. I assume it is the angle of inclination of the plane's path since it is 880 ft higher 12 seconds later.

But then, what does the statement that it "has advanced 123 degrees" mean?This is a very unclear/poorly posed question.
 
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