Calculating Al Foil Thickness in mm

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SUMMARY

The discussion focuses on calculating the thickness of aluminum foil given its area of 1.000 ft² and mass of 3.636 g, using the density of aluminum at 2.699 g/cm³. The formula for density, d = m/v, is central to the solution. The correct approach involves converting the area to cm² and using the mass to find the volume, which ultimately leads to the calculation of thickness in millimeters. The initial guess of 1.347 was incorrect due to unit discrepancies and lack of proper calculations.

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  • Understanding of density calculations (d = m/v)
  • Knowledge of unit conversions (ft² to cm²)
  • Familiarity with the properties of aluminum, specifically its density
  • Basic algebra for solving equations
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Homework Statement



A Sheet of aluminum(Al) foil has a total area of 1.000ft^2 and a mass of 3.636g.

What is the thickness of the foil in millimeters (density of Al=2.699g/cm^3)?

Homework Equations



d=m/v



The Attempt at a Solution



1.347=totally wrong... help please
 
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1.347 is probably the right answer in some system of units :-p

Also, what is the d in your "relevant equations"? Is it the d for density? Or is it the d that is sometimes used for small distances (such as, say, thickness?) And what is v? How do you calculate it from the given data?

Your "attempt" is not so much an attempt from which we can clearly locate some error, as some numerical guess, without units or any other relevant information.
 
thank you
 
You're welcome.
I take it this means you solved it?
 

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