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Help! BIF Calculation thickness of annual layer of ore

  • Thread starter kndietz
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  • #1
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Please I need help ASAP! This is the problem:
Cowen cites the deposition rate of BIF in the Hamersley Basin of Australia as 30 million metric tonnes per year. He says the ore is 55% iron (volume); iron has a density of 8 g/cm^3. Assume the rest of the ore is made of silica, which has a density of 2.6 g/cm^3. Using these data, calculate the volume of ore that was deposited aannually at Hamersley (recall that density = mass per unit volume). The Hamersley Basic is roughly circular ((we were told to consider it cylinder)), about 400 km in diameter. How thick was an annual layer of ore?

My teacher said we need to get average density, then volume, finally thickness. But I still have no idea how to go about doing this homework!!
 

Answers and Replies

  • #2
Evo
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I'm going to move this for you, but you still need to show what you have done to solve this yourself.
 
  • #3
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I have tried to start calculating the density but I am stumped on how to do this without mass, and in order to find volume you need density....
I tried converting from cm^3 to m^3, .08 and .026, and then I tried to make this into the 55% and 45% they represent.... 4.4 and 1.17, combined is 5.57.
I really don't know if this is the right place to start or not, or where to go from here.
 
  • #4
Borek
Mentor
28,360
2,753
Imagine you have 100kg of BIF. Can you calculate its volume from a given data?

More elegant approach calls for assuming you have m kg of BIF and solving for the volume/density using this unknown - you will find m cancels out in the end.
 

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