Calculating Amplitude for a Spring Oscillation with Hooke's Law

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SUMMARY

The discussion focuses on calculating the amplitude of a spring oscillation using Hooke's Law. A 2 kg block is attached to a spring, and 16 J of energy is supplied to stretch it. The period of oscillation is given as 0.3 seconds. The correct amplitude is determined to be 0.38 m (or 38 cm) after solving the equations for potential energy and spring constant, confirming that the amplitude is half the initial displacement.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with simple harmonic motion (SHM) equations
  • Knowledge of potential energy in springs (Usp = 1/2(k)(xs)^2)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the spring constant (k) from the period formula T = 2π√(m/k)
  • Learn about energy conservation in simple harmonic motion
  • Explore different types of amplitude (peak-to-peak vs. maximum amplitude)
  • Practice solving problems involving oscillations and spring systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators teaching concepts related to Hooke's Law and simple harmonic motion.

  • #31


Okay, I redid it using the new equation. I think I got the same things you did, which is good. :) But my question is: are we doubling it for the same reason we did before? (A = 2x)
 
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  • #32


Dark Visitor said:
Okay, I redid it using the new equation. I think I got the same things you did, which is good. :) But my question is: are we doubling it for the same reason we did before? (A = 2x)

There are many kinds of amplitude: peak-to-peak and what is being used here as in

A cos(wt). Apparently they just want A. Whew glad that's over. I'm going to leave you in the good hands of whomever for the last problem before I kill us both with confusion. :biggrin:

BTW, the equation is the same, just more legible by taking out the extra divisor sign which is what led to the bunged algebra. Don't feel bad, do it all the time myself.
 
  • #33


Okay, I think I can get that one eventually. There is a guy on there helping me now, so thanks to both of you for your help. I know it was a pain in the butt. But I appreciate it. :approve:
 

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