Dark Visitor
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Okay, I redid it using the new equation. I think I got the same things you did, which is good. :) But my question is: are we doubling it for the same reason we did before? (A = 2x)
Calculating Amplitude for a Spring Oscillation with Hooke's Law
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Okay, I redid it using the new equation. I think I got the same things you did, which is good. :) But my question is: are we doubling it for the same reason we did before? (A = 2x)
denverdoc
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Dark Visitor said:
There are many kinds of amplitude: peak-to-peak and what is being used here as in
A cos(wt). Apparently they just want A. Whew glad that's over. I'm going to leave you in the good hands of whomever for the last problem before I kill us both with confusion.
BTW, the equation is the same, just more legible by taking out the extra divisor sign which is what led to the bunged algebra. Don't feel bad, do it all the time myself.
Dark Visitor
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Okay, I think I can get that one eventually. There is a guy on there helping me now, so thanks to both of you for your help. I know it was a pain in the butt. But I appreciate it.
