(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A spring with spring constant 10.5 N/m hangs from the ceiling. A 520 g ball is attached to the spring and allowed to come to rest. It is then pulled down 6.20 cm and released.

What is the time constant if the ball's amplitude has decreased to 2.70 cm after 60.0 oscillations?

2. Relevant equations

I used:

T= 2π√m/k

A(t) = A(0)e^-λt

-I apologize for the notation, still learning how to post...

3. The attempt at a solution

Plugging into the equation for T I found the period to be 1.398 s

After 60 oscillations 83.895 seconds will have passed

This is the t I used in the amplitude function.

The initial amplitude is 0.0062 m

The final amplitude is 0.0027 m

0.0027 = 0.0062e^-λt

.43548 = e^-λt

ln(.43548)=-λt

ln(.43548)=-λ(83.895)

0.0099=λ

The time constant is 1/λ = 100.921

This is where I ended up and it is obviously wrong...haha. Any help would be greatly appreciated.

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# Homework Help: Finding Amplitude of spring oscillation after damping

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