Calculating Angular Acceleration: A Flywheel Question Explained

  • Thread starter Thread starter janiexo
  • Start date Start date
  • Tags Tags
    Flywheel
Click For Summary
The discussion centers on calculating the angular acceleration of a flywheel given a constant force and the unwinding of rope. Participants clarify that the problem requires understanding torque and angular acceleration, which are proportional due to the constant force applied. It is emphasized that the moment of inertia does not need to be calculated for this specific problem. The average angular velocity can be determined, leading to the calculation of angular acceleration over the given time period. The confusion about which type of angular acceleration to use is resolved, as all forms are the same in this scenario.
janiexo
Messages
29
Reaction score
0
"A flywheel 0.600 m in diameter pivots on a horizontal axis. A rope is wrapped around the outside of the flywheel, and a steady pull of 40.0 N is exerted on the rope. The flywheel starts from rest, and 5.00 m of rope are unwound in 2.00 s.
1. What is the angular acceleration of the flywheel?"


I'm just confused with this question because I'm wondering whether they want the average angular acceleration, or the angular acceleration at the beginning or at the end.

I tried to solve it by saying that angular velocity = velocity/radius where the velocity is equal to d/t (5/2) and radius is 0.3, then used angular acceleration = angular velocity/time where time = 2 and got an answer of 25/6 but it was wrong. I'm probably all over the place but I'm new to these angular concepts so any help would be appreciated
 
Physics news on Phys.org
janiexo said:
"A flywheel 0.600 m in diameter pivots on a horizontal axis. A rope is wrapped around the outside of the flywheel, and a steady pull of 40.0 N is exerted on the rope. The flywheel starts from rest, and 5.00 m of rope are unwound in 2.00 s.
1. What is the angular acceleration of the flywheel?"


I'm just confused with this question because I'm wondering whether they want the average angular acceleration, or the angular acceleration at the beginning or at the end.

I tried to solve it by saying that angular velocity = velocity/radius where the velocity is equal to d/t (5/2) and radius is 0.3, then used angular acceleration = angular velocity/time where time = 2 and got an answer of 25/6 but it was wrong. I'm probably all over the place but I'm new to these angular concepts so any help would be appreciated

Your problem requires understanding of the concepts of moment of inertia and torque. The angular acceleration in the problem is constant because the force is constant. The angular velocity will be constantly changing. You have the average angular velocity, from which you can find the change in angular velocity from which you can find the constant angular acceleration.
 
Last edited:
So do I have to find the moment of Inertia of the wheel? How can I do that without knowing its mass?
 
Never mind, I found another topic on the board with a similar problem
 
janiexo said:
So do I have to find the moment of Inertia of the wheel? How can I do that without knowing its mass?

Just to wrap this up: In this problem you do not have to calculate the moment of inertia. You just need to understand that torque and angular acceleration are proportional. (We call that ratio the moment of inertia.) Because they are proportional, and because the torque is generated by a force that in this problem is a constant, the torque is constant and consequently the angular acceleration is constant. So your original question about "which aceleration" to use is answered by the fact that they are all the same. The information given in the problem allows you to compute the average angular velocity, which for constant angular acceleration is half-way between the initial angular velocity and the final angular velocity. From that you can find the change in angular velocity during the time period, and from that you can find the angular acceleration.
 
why is time period of flywheel infinity at it's center of gravity?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 7 ·
Replies
7
Views
6K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
44
Views
5K
  • · Replies 3 ·
Replies
3
Views
27K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
5
Views
2K
Replies
1
Views
2K