Calculating Angular Acceleration of a Shaft

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To calculate the angular acceleration of a shaft with a given radius "r" and RPM, it's important to determine if the RPM is constant. If the RPM is constant, the angular velocity remains unchanged, resulting in zero angular acceleration. The discussion suggests that a constant RPM indicates uniform rotational motion, meaning there is no change in angular velocity over time. The original question may have intended to address centripetal acceleration instead of angular acceleration. Understanding these distinctions is crucial for accurate calculations in rotational dynamics.
elmariachi
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I have a shaft with radius "r" running at a certain RPM. how can i determine the angular acceleration of the shaft. Do i need any other parameters as well? Can i say that the angular acceleration can be (w^2*r), w is the angular velocity, r being the radius.

thanks
 
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is the "certain RPM" a constant? If so, change in angular velocity of time has to be zero.
 
HungryChemist said:
is the "certain RPM" a constant? If so, change in angular velocity of time has to be zero.

In fact, any time an RPM is given it is meant that the rotatory motion is uniform, i.e. the angular velocity is a constant and , therefore, the angular acceleration is zero. Perhaps the problem meant to ask the centripetal acceleration?

J
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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