Calculating Angular Velocity and Torque of Big Ben's Hands

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The discussion focuses on calculating the angular velocity, moment of inertia, rotational kinetic energy, and angular momentum for the minute and hour hands of Big Ben, which are modeled as uniform rods. Participants express confusion about the appropriate equations to use, with some correctly identifying angular velocity as the change in angle over time and angular momentum as the product of moment of inertia and angular velocity. There is clarification on the moment of inertia, noting it requires specific formulas for distributed mass rather than a simple point mass equation. Additionally, the torque equation is discussed, with participants seeking clarity on its components. Overall, the thread highlights the challenges of applying physics concepts to this specific problem.
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Homework Statement


The minute hand of big ben is made of copper, has a length of 4.27 meters, and a mass of 101.6kg. The hour hand is made of gunmetal, has a length of 2.74m, and a mass of 304.8kg. Assume that each hand is a uniform rod and rotates about one end. Use a cartesian coordinate system with +x to the right, +y up, and +z out of page. Find the angular velocity, the moment of inertis, the rotational KE, and the angular momentum of the minute and hour hand. Then calculate the torque of the drive shaft owing to the weight if the hand acting at its center of mass when the arm points to the numbers 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12. Torque=R x F AT There should be 34 answers in all.


Homework Equations


I don't know where to start with this problem because I don't know which equations to use.
Angular velocity= delta theta/ delta time??
moment of inertia= mr squared ((g Tm squared/ 2h) -1)?
rotational KE= theta final-theta initial/ tfinal- tinitial?


The Attempt at a Solution



My attempt at a solution failed because I do not think the equations are correct. I have been trying this problem for a week and can not figure it out. I do not even know where to start from.
 
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dban33 said:
I don't know where to start with this problem because I don't know which equations to use.
Angular velocity= delta theta/ delta time??
moment of inertia= mr squared ((g Tm squared/ 2h) -1)?
rotational KE= theta final-theta initial/ tfinal- tinitial?

My attempt at a solution failed because I do not think the equations are correct.

Hi dban33! :smile:

(have a theta: θ and an omega: ω and a delta: ∆ and a squared: ² :smile:)

Angular velocity = ∆θ/∆t

Angular momentum = Iω

Rotational energy = (1/2)Iω²​

Moment of inertia (I) is only mr² for a point mass.

For something spread-out like a disc or a bar, you have to calculate the m.i. using calculus … or just look it up in a book!
 


Ok so I had the angular velocity correct but I do not have time to put into the equation. For the angular momentum what are I and ω?? Also, for the torque equation Torque= R x F AT...what do all of those letters mean?
 
dban33 said:
Ok so I had the angular velocity correct but I do not have time to put into the equation. For the angular momentum what are I and ω?? Also, for the torque equation Torque= R x F AT...what do all of those letters mean?

I is moment of inertia.

ω is angular velocity.

Torque = distance (R) "cross" force (F).

I don't know what AT means … I expect it's a misprint.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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