1. The problem statement, all variables and given/known data 1 m long rotatable bar with a mass of 2 kg is held on vertical stick that goes through its center of gravity. A bullet with mass 0.2 kg is shot with a speed 1 m/s horizontally at the edge of the bar. After the collision the bullet lodges into the bar. Calculate the angular velocity of the bar after the collision, if the bar was at rest at the beginning? 2. Relevant equations Conservation of the angular moment 3. The attempt at a solution mRv= (MR + mR + I) ω ω= mRv / (MR² + mR² + MR²/12) ω= mv / (MR + mR + MR/12) ω= 0.17 m/s Are my calculations correct?